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Questions  

A  =  2i^+j^,  B=3j^k^   and  C  =  6i^2k^.  Valueof  A2B+3C would be

a
20i^ +5j^ +4k^
b
20i^ −5j^ −4k^
c
4i^ +5j^ +20k^
d
5i^ +4j^ +10k^

detailed solution

Correct option is B

A→−2B→ +3C→  = (2i^+j^)−2(3j^−k^)+3(6i^−2k^)= 2i^+j^−6j^+2k^+18i^−6k^= 20i^−5j^−4k^

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