An ice cube of size l = 50 cm is floating in a tank (base area A=2m×2m) partially filled with water. water is Density of ρw=1000 kgm−3 and that of ice is ρice=900 kg−3 Calculate change increase in gravitational potential energy (in J) when ice melts completely. (g = 10 ms-2)

As the density of the ice ρice  is less than the density of the water ρwater , hence the ice cube float partially immersed.In case of floatationBuoyancy force = weight of cubeB=mg or l2h0ρwater g=l3ρice g⇒ h0=l×ρice ρwater =50×9001000=45cmCentre of mass of ice cube is at a depth of 25 cm from its upper surface. But the upper surface is at a height of 5 cm from water surface.Therefore, depth of the centre of the mass of ice cube from free water surface is h1 = 25 - 5 = 20 cm from free water surface.When ice melts, water is formed and that water occupies the space which was displaced by the cube. Therefore, depth of centre of mass of the water body formed after the melting of ice cube is h2=452=22.5cmit means that the centre of mass move down through distanceΔh=h2−h1=22.5−20=2.5cmlt means gravitational potential energy of the system will decrease. Decrease in gravitational potential energy of the systemΔU=mgΔh=(0.5)3×1000×10×2.51000=31.25JSince, level of free water surface does not rise or fall, hence size of tank is of no concern.