Ice at 0oC mixed with 200 gm of water at 20oC. If final mixture at equilibrium contains five times water than ice,the initial mass of ice was(Water Cwater=1cal/gm−α,Lice=80cal/gm−oC)

Let initial mass of ice be ‘m’ gmAlso let mass of ice melted be ‘x’ gm∴(200+x)=5(m−x)⇒m=x+x5+40=6x5+40gm      ......(1)Also,  x×80=200×1×(20−0)⇒x=50gm    .......(2)∴m=6×505+40gm=100gm