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Ice at $0^{o} C$ mixed with 200 gm of water at $20^{o} C$ . If final mixture at equilibrium contains five times water than ice,the initial mass of ice was
$(Water C_{water} = 1 cal / gm - α, L_{ice} = 80 cal / gm -^{o} C)$

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Correct option is B

Let initial mass of ice be ‘m’ gmAlso let mass of ice melted be ‘x’ gm∴(200+x)=5(m−x)⇒m=x+x5+40=6x5+40gm ......(1)Also, x×80=200×1×(20−0)⇒x=50gm .......(2)∴m=6×505+40gm=100gm

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Ice at 0oC mixed with 200 gm of water at 20oC. If final mixture at equilibrium contains five times water than ice,the initial mass of ice was(Water Cwater=1cal/gm−α,Lice=80cal/gm−oC)

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Ready to Test Your Skills?

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Ice at $0^{o} C$ mixed with 200 gm of water at $20^{o} C$ . If final mixture at equilibrium contains five times water than ice,the initial mass of ice was
$(Water C_{water} = 1 cal / gm - α, L_{ice} = 80 cal / gm -^{o} C)$