Ice at $0^{\mathrm{o}}\mathrm{C}$ mixed with 200 gm of water at ${20}^{\mathrm{o}}\mathrm{C}$. If final mixture at equilibrium contains five times water than ice,the initial mass of ice was

$(\mathrm{Water}{\mathrm{C}}_{\mathrm{water}}=1\mathrm{cal}/\mathrm{gm}-\mathrm{\alpha },{\mathrm{L}}_{\mathrm{ice}}=80\mathrm{cal}/\mathrm{gm}{-}^{\mathrm{o}}\mathrm{C})$

• A

   50 gms 

• B

  100 gms

• C

  125 gms

• D

  75 gms