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Q.

An iceberg is floating partially immersed in sea water. The density of sea water is 1.03 g cm-3 and that of ice is 0.929 cm-3. The approximate percentage of total volumeof iceberg above the level of sea water is

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a

8

b

11

c

34

d

89

answer is B.

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Detailed Solution

B=mg⇒(V−ΔV)×1.03×g=V×0.92×g⇒V−ΔVV=0.921.03⇒ ΔVV=1−0.921.03=0.111.03   ⇒ΔVV×100=111.03≈11
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