An ideal Carnot’s engine with an efficiency of 30% operates between a source and a sink. If the temperature of the source is 500 K, that of the sink is

Efficiency of Carnot’s engine,η= 30% = 0.3 Temperature of source,T1= 500 K Temperature of sink, T2=? We know that, efficiency of Carnot engine, η=1−T2T10.3=1−T2500T2500=1−0.3⇒T2=0.7×500=350 K = (350−273)0C=770C