An ideal coil of 10 H is joined in series with a resistance of 5 Ω and a battery of 5 V. 2 s after joining, the current flowing in ampere in the circuit will be
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a
e-1
b
1-e-1
c
1-e
d
e
answer is B.
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Detailed Solution
From i=i01-e-Rt/L, where i0=55=1 A ∴i=11-e-5×210=1-e-1A