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Q.

An ideal coil of 10 H is joined in series with a resistance of 5 Ω and a battery of 5 V. 2 s after joining, the current flowing in ampere in the circuit will be

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a

e-1

b

1-e-1

c

1-e

d

e

answer is B.

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Detailed Solution

From i=i01-e-Rt/L, where i0=55=1 A ∴i=11-e-5×210=1-e-1A
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