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Q.

An ideal diatomic gas undergoes an isothermal expansion shown by AB curve in the P-V diagram. The amount of heat absorbed by the gas during this process is (take loge5 = 0.7)

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a

5PoVo/2

b

9PoVo/2

c

7PoVo/2

d

3PoVo/2

answer is C.

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Detailed Solution

ΔQ = ΔU + ΔWΔU = nCvΔT = nCv(0) = 0In isothermal process ΔW = nTRloge(V2/V1). Using PV = nTR, we get nTR value as 5PoVo and using loge5 = 0.7, ΔW = 3.5 PoVo
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