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An ideal diatomic gas undergoes an isothermal expansion shown by AB curve in the P-V diagram. The amount of heat absorbed by the gas during this process is (take loge5 = 0.7)

a
5PoVo/2
b
9PoVo/2
c
7PoVo/2
d
3PoVo/2

detailed solution

Correct option is C

ΔQ = ΔU + ΔWΔU = nCvΔT = nCv(0) = 0In isothermal process ΔW = nTRloge(V2/V1). Using PV = nTR, we get nTR value as 5PoVo and using loge5 = 0.7, ΔW = 3.5 PoVo

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