First slide

Different type of processes

Question

An ideal diatomic gas undergoes an isothermal expansion shown by AB curve in the P-V diagram. The amount of heat absorbed by the gas during this process is (take loge5 = 0.7)

Moderate

A

5PoVo/2
B

9PoVo/2
C

7PoVo/2
D

3PoVo/2

Solution

ΔQ = ΔU + ΔW
ΔU = nC_vΔT = nC_v(0) = 0
$\therefore \Delta Q = \Delta W$
In isothermal process ΔW = nTRlog_e(V₂/V₁). Using PV = nTR, we get nTR value as 5PoVo and using log_e5 = 0.7, ΔW = 3.5 PoVo

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