First slide
In YDSE one of the slits is covered with a thin transparent sheet
Question

In the ideal double slit experiment, when a glass-plate refractive index 1 .5) of thickness t is introduced in the path of one of the interfering beams (wavelength i,,) the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is

Moderate
Solution

. Minimum thickness corresponds to a shift equal to β Hence 
(μ1)tD(2d)=λD(2d) or t=λ(μ1)=λ(151)=λ05=2λ

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