In an ideal double-slit experiment, when a glass plate (refractive index 1 .5) of thickness t is introduced in the path of one of the interfering beams {wavelength λ ) the intensity at the position where the central maximum occurred previously remains unchanged' The minimum thickness of the glass-plate is
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a
2λ
b
2λ/3
c
λ/3
d
λ
answer is A.
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Detailed Solution
the path difference is given by (μ−1)t=λ(for minimum) t=λ(μ−1)=λ(1⋅5−1)=λ0⋅5=2λ