First slide
In YDSE one of the slits is covered with a thin transparent sheet
Question

 In an ideal double-slit experiment, when a glass plate (refractive index 1 .5) of thickness t is introduced in the path of one of the interfering beams {wavelength λ ) the intensity at the position where the central maximum occurred previously remains unchanged' The minimum thickness of the glass-plate is

Easy
Solution

the path difference is given by (μ1)t=λ(for minimum) 
t=λ(μ1)=λ(151)=λ05=2λ

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