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Q.

An ideal fluid is flowing through the given tubes which is placed on a horizontal surface. If the liquid has velocities VA and VB, and pressures PA and PB at points A and B respectively, then the correct relation is (A and B are at same height from ground level, the figure shown is as if the system is seen from the top):

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a

VA > VB, PA

b

VAPB

c

VA = VB, PA = PB

d

VA>VB, PA = PB

answer is C.

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Detailed Solution

Applying continuity equation:        V1A1 = V2A2         A1 = A2 so V1 = V2Applying Bernoulli's equation:P1+ρgh1+12ρv12 = P2+ρgh2+12ρv22since v1 = v2; and h1 = h2⇒P1 = P2
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