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Q.

An ideal fluid flows in the pipe as shown in the figure. The pressure in the fluid at the bottom P2 is the same as it is at the top P1. If the velocity of the top v1 = 2 m/s. Then the ratio of areas A1 . A2is

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a

2 : 1

b

4 : 1

c

8 : 1

d

4 : 3

answer is B.

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Detailed Solution

Using equation of continuity, we havev2=A1A2v1From Bernoulli's theorem,p1+ρgh1+12ρv12p2+ρgh2+12ρv22⇒g(h1−h2)=12(v22−v12)⇒60=A12A22−1v12⇒A1A2=41

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