An ideal fluid flows through a pipe of circular cross section made of two sections with diameter 2.5 cm and 3.75 cm. The ratio of the velocities in the two pipes is
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a
9 :4
b
3 : 2
c
3 : 2
d
2 : 3
answer is A.
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Detailed Solution
According to equation of continuity A1v1 = A2v2v1v2 = A2A1 = πD224πD124 = (D2D1)2Here D1 = 2.5 cm, D2 = 3.75 cm∴ v1v2 = (3.752.5)2 = (32)2 = 94