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Q.

An ideal fluid flows through a pipe of circular cross section made of two sections with diameter 2.5 cm and 3.75 cm. The ratio of the velocities in the two pipes is

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a

9 :4

b

3 : 2

c

3 : 2

d

2 : 3

answer is A.

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Detailed Solution

According to equation of continuity A1v1 = A2v2v1v2 = A2A1 = πD224πD124 = (D2D1)2Here D1 = 2.5 cm, D2 = 3.75 cm∴  v1v2 = (3.752.5)2 = (32)2 = 94
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