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Q.

An ideal fluid flows through two pipes of circular cross-section with diameters 2.5 cm and 3.75 cm connected one after another. The ratio of the velocities in the two pipes is

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a

9:4

b

3:2

c

3:2

d

2:3

answer is A.

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Detailed Solution

As givend1 = Diameter of 1st pipe is 2.5 cm.d2 = Diameter of IInd pipe is 3.75 cm.Applying equation of continuity for cross-sections A1  and A2.A1v1=A2v2⇒ v1v2=A2A1=πr22πr12=r2r12=3.7522.522=3.752.52=94
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