An ideal fluid flows through two pipes of circular cross-section with diameters 2.5 cm and 3.75 cm connected one after another. The ratio of the velocities in the two pipes is
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a
9:4
b
3:2
c
3:2
d
2:3
answer is A.
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Detailed Solution
As givend1 = Diameter of 1st pipe is 2.5 cm.d2 = Diameter of IInd pipe is 3.75 cm.Applying equation of continuity for cross-sections A1 and A2.A1v1=A2v2⇒ v1v2=A2A1=πr22πr12=r2r12=3.7522.522=3.752.52=94