For an ideal gas

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the change in internal energy in a constant pressure process from temperature T1 to T2 is equal to nCVT2−T1, where C, is the molar specific heat at constant volume and n the number of moles of the gas.

the change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.

the internal energy does not change in an isothermal process.

no heat is added or removed in an adiabatic process.

answer is A.

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Detailed Solution

(a) ΔV=mCVΔT=nCVT2−T1 (b) dQ=dU+dWbut dQ=0 (adiabatic process) ∴ dU=−dW or |dU|=|dW| (c) dU=mCV,dT (dT=0, isothermal process )∴ dU=0 (d) dQ=0 in adiabatic change. Hence all are correct.

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