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a
the change in internal energy in a constant pressure process from temperature T1 to T2 is equal to nCVT2−T1, where C, is the molar specific heat at constant volume and n the number of moles of the gas.
b
the change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.
c
the internal energy does not change in an isothermal process.
d
no heat is added or removed in an adiabatic process.
answer is A.
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Detailed Solution
(a) ΔV=mCVΔT=nCVT2−T1 (b) dQ=dU+dWbut dQ=0 (adiabatic process) ∴ dU=−dW or |dU|=|dW| (c) dU=mCV,dT (dT=0, isothermal process )∴ dU=0 (d) dQ=0 in adiabatic change. Hence all are correct.