An ideal gas goes from state A to state B via three different processes A as indicated in the p -V I diagram lf Q1, Q2, Q3 indicate the heat absorbed P by the gas along the three processes and ∆U1, ∆U2, ∆U3 indicate the change in internal energy along the three processes respectively, then

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Q1 > Q2 > Q3 and ∆U1 = ∆U2 = ∆U3

Q1 > Q2 > Q1 and ∆U1 = ∆U2 = ∆U3

Q1 = Q2 = Q3 and ∆U1 > ∆U2 > ∆U3

Q1 > Q2 > Q3 and ∆U1 > ∆U2 > ∆U3

answer is A.

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Detailed Solution

For all processes 1,2 arrd3∆U = UB-UA is the same∴ ∆U1 = ∆U2 = ∆U3Now, Q = ∆U + WNow, W = work done by the gas∴ Q1 > Q2 > Q3

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