First slide

Specific heat

Question

An ideal gas has molar specific heat 5R/2 at constant pressure. If 300 J of heat is given to two moles of gas at constant pressure, the change in temperature is:

Easy

A

7.22°C
B

8.94°C
C

zero
D

5°C

Solution

$Q = {nC}_{P} ∆ T = \frac{Q}{{nC}_{P}} = \frac{300}{2 \times \frac{5 R}{2}} = \frac{60}{R} = 7 . 22^{o} C$

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