An ideal gas has a volume of 3 V at 2 atmosphere pressure. Keeping the temperature constant, its pressure is doubled. The volume of the gas will be:
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a
6 V
b
3 V
c
1.5 V
d
1 V
answer is C.
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Detailed Solution
Initial volume V1 = 3VInitial pressure P1 = 2 atmosphereFinal pressure P2 = 2P1 = 2 × 2 = 4 atmosphereAccording to the Boyle's law we haveP1V1 = P2V2(where V2 is the final volume of gas)or 2 × 3V = 4×V2 or V2 = 1.5 V