Questions
An ideal gas has a volume of 3 V at 2 atmosphere pressure. Keeping the temperature constant, its pressure is doubled. The volume of the gas will be:
detailed solution
Correct option is C
Initial volume V1 = 3VInitial pressure P1 = 2 atmosphereFinal pressure P2 = 2P1 = 2 × 2 = 4 atmosphereAccording to the Boyle's law we haveP1V1 = P2V2(where V2 is the final volume of gas)or 2 × 3V = 4×V2 or V2 = 1.5 VTalk to our academic expert!
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Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of B being twice that of A. under such conditions. The density of A is found to be one-third of the density of B. the ratio of molecular weight of A and B is
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