First slide

laws

Question

An ideal gas has a volume of 3 V at 2 atmosphere pressure. Keeping the temperature constant, its pressure is doubled. The volume of the gas will be:

Easy

A

6 V
B

3 V
C

1.5 V
D

1 V

Solution

Initial volume $V_{1} = 3 V$
Initial pressure $P_{1} = 2 atmosphere$
Final pressure
$P_{2} = 2 P_{1} = 2 \times 2 = 4 atmosphere$
According to the Boyle's law we have
$P_{1} V_{1} = P_{2} V_{2} (where V_{2} is the final volume of gas)$
or $2 \times 3 V = 4 \times V_{2} or V_{2} = 1.5 V$

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