Q.
An ideal gas heat engine operates in Carnot cycle between 2270C and 1270C . It absorbs 6×104 cals of heat at higher temperature. Amount of heat converted to work is (in cal)
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a
2.4×104
b
6×104
c
1.2×104
d
4.8×104
answer is C.
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Detailed Solution
η=T1−T2T1=WQ⇒W=Q(T1−T2)T1 =6×104[(227+273)−(273+127)](227+273) =6×104×100500=1.2×104cal
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