An ideal gas heat engine operates in Carnot cycle between 227oC and 127oC.It absorbs 6 x 104 cals of heat at higher temperature. Amount of heat converted to work is

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2.4×104cal

6×104cal

1.2×104cal

4.8×104cal

answer is C.

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Detailed Solution

η=T1−T2T1=WQ⇒W=QT1−T2T1=6×104[(227+273)−(273+127)](227+273)=6×104×100500=1.2×104cal

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