First slide

Heat engine

Question

An ideal gas heat engine operates in a Carnot cycle between 27°C and 127°C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

Moderate

A

3.5
B

1.6
C

1.5
D

4.8

Solution

Efficiency of a carnot engine is given by $η = 1 - \frac{T_{2}}{T_{1}}$
$or \frac{W}{Q} = 1 - \frac{T_{2}}{T_{1}} \Rightarrow \frac{W}{6} = 1 - \frac{(273 + 27)}{(273 + 127)} \Rightarrow W = 1 .5 kcal$

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