First slide

Heat engine

Question

An ideal gas heat engine operates in a Carnot cycle between 227^oC and 127^oC. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

Easy

A

4.8
B

3.5
C

1.6
D

1.2

Solution

$η = 1 - \frac{T_{2}}{T_{1}} = \frac{W}{Q} \Rightarrow \frac{W}{6} = 1 - \frac{400}{500} \Rightarrow W = 1.2 kcal$

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