An ideal gas is initially at temperature T and volume V. Its volume is increased by ∆V due to an increase in temperature ∆T, pressure remaining constant. The quantity δ $$=$$ ∆$$V/(V$$ ∆$$T)$$ varies with temperature as

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An ideal gas is initially at temperature T and volume V. Its volume is increased by ∆V due to an increase in temperature ∆T, pressure remaining constant. The quantity δ $$=$$ ∆$$V/(V$$ ∆$$T)$$ varies with temperature as

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From ideal gas equation, pV $$=$$ RT                                 …(i)or$$                  p∆V $$=$$ R∆T                                             …$$(ii)On$$ dividing Eq. $$(ii) by Eq. (i), we get                        Δ$$VV=$$ΔTT⇒ΔVVΔ$$T=1T=$$δ           (Given)∴                   δ $$=$$ $$1TSo$$, the graph between δ and T will be rectangular hyperbola.

An ideal gas is initially at temperature T and volume V. Its volume is increased by $∆$ V due to an increase in temperature $∆$ T, pressure remaining constant. The quantity $δ = ∆ V / (V ∆ T)$ varies with temperature as

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An ideal gas is initially at temperature T and volume V. Its volume is increased by ∆V due to an increase in temperature ∆T, pressure remaining constant. The quantity δ = ∆V/(V ∆T) varies with temperature as

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An ideal gas is initially at temperature T and volume V. Its volume is increased by $∆$ V due to an increase in temperature $∆$ T, pressure remaining constant. The quantity $δ = ∆ V / (V ∆ T)$ varies with temperature as