Q.

An ideal gas at 27oC is compressed adiabatically to 8/27 of its original volume. If γ = 513, then the rise in temperature is

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a

450 K

b

375 K

c

225 K

d

405 K

answer is B.

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Detailed Solution

For an adiabatic process TVγ−1= constant . Therefore, T1T2=V2V1γ−1⇒ T2=T1V1V2γ−1=3002785/3−1=3002782/3=675K⇒ ΔT=675−300=375K
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