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An ideal gas is subjected to a cyclic process involving four thermodynamic states; the amounts of heat (Q) and work (W) involved in each of these states are
Q1 = 6000 J, Q2 = – 5500 J ;  Q3 = – 3000 J; Q4 = 3500 J
W1 = 2500 J; W2 = – 1000 J; W3 = – 1200 J; W4 = xJ.
The ratio of the net work done by the gas to the total heat abosrbed by the gas is 'η'. The values of x and 'η' respetively are

a
500 ; 7.5%
b
700 ; 10.5%
c
1000 ; 21%
d
1500 ; 15%

detailed solution

Correct option is B

Incyclic process Δu = 0Qnet = Wnet6000–5500–3000+3500 = 2500–1000–1200+xx = 700 JWnet = (2500 - 1000 - 1200 + 700)J= 1000Heat supplied Q1 = (6000 + 3500)J= 9500 J.

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