First slide

First law of thermodynamics

Question

An ideal gas is taken through the cycle $A \to B \to C \to A$ as shown in fig. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process
$C \to A$ is

Moderate

A

-5 J
B

-10 J
C

-15 J
D

-20 J

Solution

For cyclic process,
$Q_{cyclic} = W_{AB} + W_{BC} + W_{CA}$
Here $W_{AB} = 10 (2 - 1) = 10 J, W_{BC} = 0$
$∴ 5 J = 10 J + 0 + W_{CA} or W_{CA} = - 5 J$ .

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App