An ideal gas is taken through the cycle A→B→C→A as shown in fig. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C→A is
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a
-5 J
b
-10 J
c
-15 J
d
-20 J
answer is A.
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Detailed Solution
For cyclic process,Qcyclic =WAB+WBC+WCAHere WAB=10(2−1)=10J,WBC=0∴ 5J=10J+0+WCA or WCA=−5J.