An ideal gas is taken through the cycle A→B→C→A, as shown. If the net heat supplied to the gas in the cycle is 5J, the work done by the gas in the process C→A is
-5 J
-10 J
-15 J
-20 J
For cyclic process ΔU=0
So, ΔQ=ΔW5=ΔWAB+ΔWBC+ΔWCA5=10+0+ΔWCAΔWCA=−5J