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An ideal gas is taken through the cycle , as shown in figure. If the net heat supplied to the gas in the cycle is 5 J, work done by the gas in the process
detailed solution
Correct option is A
given graph has pressure along horizontal axis, volume in meter3 along vertical axiswork done from A to B is WA→B=PdV=10[2-1]=10 J, here volume is increasedwork done from B to C is WB→C=PdV=0, here there is no change in volumework done from C to A is WC→A=?In cyclic process dU=0,( change in internal energy) from first law of thermodynamics dQ=dU+dWhere dQ=change in heat energy=5JdU=change in inernal energydW=work done substitute in first law of thermodynamics ⇒5=0+[WA→B+WB→C+WC→A] ⇒5=10+0+WC→A ⇒WC→A=5−10 ⇒WC→A=−5 JTalk to our academic expert!
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An ideal gas expands isothermally from a volume V1 to V2 and then compressed to original volume V1 adiabatically. Initial pressure is P1 and final pressure is P3. The total work done is W. Then
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