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Q.

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are Q1=5960  J,Q2=−5585J,Q3=−2980J and Q4=3645J respectively. The corresponding works involved are W1=2200J,W2=−825J,W3=−1100J, and W4 respectively what is the efficiency of the cycle approximately?

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a

11%

b

22%

c

33%

d

44%

answer is A.

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Detailed Solution

For cyclic processΔQ=ΔWQ1+Q2+Q3+Q4=W1+W2+W3+W4W4=765η=work  doneHeat  abserbed=W1+W2+W3+W4Q1+Q4η=10409605=0.107≈11%
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