Questions
An ideal gas whose adiabatic exponent equals to is expanded according to the law P = 2V.The initial volume of the gas is equal to unit. As a result of expansion the volume increases 4 times. (Take R = units)
Column-I | Column-II | ||
i. | Work done by the gas | p. | 25 units |
ii. | Increment in internal energy of the gas | q. | 45 units |
iii. | Heat supplied to the gas | r. | 75 units |
iv. | Molar heat capacity of the gas in the process | s. | 15 units |
t. | 55 units |
Now much the given columns and select the correct option from the codes given below.
Codes
detailed solution
Correct option is B
W = ∫ PdV = ∫V04V02VdV = (V2)V04V0 = 15V02 = 15 unitsFrom PV = nRT, 2V2 = nRT⇒2(V22-V12) = nR(∆T) nR∆T = 30V02∆U = nCv∆T = nRγ-1∆T = 30V02γ-1 = 30(1)275-1 = 30 2(5) = 75 unitsQ = W + ∆U = 15+30 = 45 unitsMolar heat capacity:C = Cv+R1-x = 52R+R1-(-1) = 52R+R2 = 3R = 3 ×253 = 25 unitsTalk to our academic expert!
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