Q.

An ideal gas whose adiabatic exponent equals to 75 is expanded according to the law P = 2V.The initial volume of the gas is equal to Vo = 1 unit. As a result of expansion the volume increases 4 times. (Take R = units)Now much the given columns and select the correct option from the codes given below.Codes

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a

i -t, ii - s, iii-q, iv-r

b

i-s, ii-r, iii-q, iv - p

c

i-q, ii - r, iii -s, iv - t

d

i - p, ii - q, iii - r, iv - s

answer is B.

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Detailed Solution

W = ∫ PdV  = ∫V04V02VdV = (V2)V04V0 = 15V02 = 15 unitsFrom PV = nRT, 2V2 = nRT⇒2(V22-V12) =  nR(∆T)    nR∆T = 30V02∆U = nCv∆T = nRγ-1∆T = 30V02γ-1 = 30(1)275-1 = 30 2(5)        = 75 unitsQ = W + ∆U = 15+30 = 45 unitsMolar heat capacity:C = Cv+R1-x = 52R+R1-(-1) = 52R+R2 = 3R    = 3 ×253 = 25 units
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An ideal gas whose adiabatic exponent equals to 75 is expanded according to the law P = 2V.The initial volume of the gas is equal to Vo = 1 unit. As a result of expansion the volume increases 4 times. (Take R = units)Now much the given columns and select the correct option from the codes given below.Codes