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Heat engine
Question

An ideal heat engine exhausting heat at 77°C is to have a 30% efficiency. It must take heat at

Easy
Solution

T2 = 350k, T1 = ?, t1 = ?

\eta = \frac{{{T_1} - {T_2}}}{{{T_1}}} \Rightarrow \frac{{30}}{{100}} = \frac{{{T_1} - {T_2}}}{{{T_1}}}

3T1 = 10T1 – 3500

7T1 = 3500

T1 = 500k  ; t1 = 500 – 273 = 227°C 

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