An ideal heat engine working between temperature T1 and T2 has an efficiency η, the new efficiency if both the source and sink temperature are doubled, will be
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a
η2
b
η
c
2η
d
3η
answer is B.
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Detailed Solution
In first case η1 = T1-T2T1In second case η2 = 2T1-2T22T1 = T1-T2T1 = η