Questions
An ideal monoatomic gas is carried around the cycle ABCDA as shown in the figure. The efficiency of the cycle is
detailed solution
Correct option is A
Efficiency = work doneheat absorbed= area of the PV diagramheat absorbed Heat absorbed in AB and BCQAB = nCvdT = 3R2n3To−To = 6RTo2(at constant volume it pressure increases to 3 times temperature also becomes 3 times) TB=3TAQBC = nCpdT = 5R2n6To−3To =15RTo2(at constant pressure if volume becomes double temperatureis also doubles) TC=2TB=6TAEfficiency = 2poVo21RTon2 = 4nRTo21nRTo =421 ,% efficiency=421 ×100=19%Talk to our academic expert!
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