An ideal refrigerator has a freezer at a temperature of -13°C. The coefficient of performance of the engine is 5. The temperature of air (to which heat is rejected) will be
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a
325˚C
b
325 K
c
39˚C
d
320˚C
answer is C.
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Detailed Solution
Coefficient of performance K=T2T1−T2⇒ 5=(273−13)T1−(273−13)=260T1−260⇒5T1−1300=260⇒5T1=1560⇒T1=312K→39∘C