An ideal refrigerator has a freezer at a temperature of -130C. The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) will be
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a
3250C
b
325K
c
390C
d
3200C
answer is C.
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Detailed Solution
Coefficient of performance K = T2T1-T2 ⇒ 5 = (273-13)T1-(273-13) = 260T1-260⇒ 5T1-1300 = 260 ⇒ 5T1 = 1560⇒T1 = 312 K ⇒t1= 390C