First slide

Electrical machines and devices

Question

An ideal transformer has 100 turns in the primary and 250 turns in the secondary. The peak value of the ac is 28 V. The r.m.s. secondary voltage is nearest to

Moderate

A

50 V
B

70 V
C

100 V
D

40 V

Solution

$\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}} \Rightarrow \frac{250}{100} = \frac{V_{s}}{28 / \sqrt{2}} \Rightarrow V_{s} = 50 V$

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