Q.
An ideal transformer has 100 turns in the primary and 250 turns in the secondary. The peak value of the ac is 28 V. The r.m.s. secondary voltage is nearest to
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a
50 V
b
70 V
c
100 V
d
40 V
answer is A.
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Detailed Solution
NsNp=VsVp⇒250100=Vs28/2⇒Vs=50 V
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