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Q.

In an ideal transformer, number of turns in primary coil are 140 and that in the secondary coil are 280. If current in the primary coil is 7A, then that in the secondary coil is

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An Intiative by Sri Chaitanya

a

14 A

b

3.5 A

c

7 A

d

4 A

answer is B.

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Detailed Solution

I1N1=I2N2⇒I2=I1N1N2⇒I2=7×140280=3.5A

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