Identical charges each of – q are placed at each corners of cube of side 'b'. Then electrostatic potential energy of charge +q which is placed at the centre of the cube will be

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-42 q2π ε0b

-82 q2π ε0b

-4q23π ε0b

82q24π ε0b

answer is C.

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Detailed Solution

Distance of center from the corner is 3b2 energy q1q2r14πεoq-q4πεo3b2×8-4q23bπεo

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