Identical charges each of – q are placed at each corners of cube of side 'b'. Then electrostatic potential energy of charge +q which is placed at the centre of the cube will be
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a
-42 q2π ε0b
b
-82 q2π ε0b
c
-4q23π ε0b
d
82q24π ε0b
answer is C.
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Detailed Solution
Distance of center from the corner is 3b2 energy q1q2r14πεoq-q4πεo3b2×8-4q23bπεo