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Q.

125 identical drops each charged to the same potential of 50 volts are combined to form a single drop. The potential of the new drop will be

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a

50 V

b

250 V

c

500 V

d

1250 V

answer is D.

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Detailed Solution

V=n2/3V⇒V=(125)2/3×50=1250 V
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