The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be

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2:1

1:2

1:4

4:1

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detailed solution

Correct option is B

Spring constant in series, S KS=K+KK+K=K2Spring constant in parallel Kp=K+K=2K∴VS=12πksM=12πK2M;VP=12πkpM=12π2KM So VS/Vp=1/2

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