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Q.

If along a uniform rod of length ℓ carrying current I, the voltage V changes with position x along the length of the rod such that dV/dx = – k, where k is a positive number, then the resistance of the rod is

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a

kℓ/2l

b

kℓ/l

c

I/kℓ

d

kℓl

answer is B.

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Detailed Solution

dV=−ldR==−lρdxAdVdx=−lρA=−k⇒R=kℓ/I II Method:  V2−V1=∫dVdℓdℓ=kL=IR
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