First slide

First law of thermodynamics

Question

If amount of heat given to a system be 50 J and work done on the system be 15 J, then change in internal energy of the system is

Easy

A

35 J
B

50 J
C

65 J
D

15 J

Solution

$dQ = dU + dW$
work done on the system is negative
$50 = dU - 15 \Rightarrow dU = 65 joule$

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