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If amount of heat given to a system be 50 J and work done on the system be 15 J, then change in internal energy of the system is

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a
35 J
b
50 J
c
65 J
d
15 J

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detailed solution

Correct option is C

dQ=dU+dWwork done on the system is negative50=dU−15       ⇒dU=65 joule


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