First slide

Introduction-Wave optics

Question

If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima is

Easy

A

25 : 16
B

5 : 3
C

16 : 1
D

25 : 9

Solution

$\frac{a_{1}}{a_{2}} = \frac{3}{5} ∴ \frac{I_{max}}{I_{min}} = \frac{{(a_{1} + a_{2})}^{2}}{{(a_{1} - a_{2})}^{2}} = \frac{(3 + 5)^{2}}{(3 - 5)^{2}} = \frac{16}{1}$

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