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If amplitude of simple harmonic motion doubles, its total energy becomes

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a
remains same
b
Four times
c
2times
d
3times

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detailed solution

Correct option is B

for a simple harmonic oscillator Total Energy = 12KA2  Energy α  A2---(1) new ampitude A'=2A new Energy α (A')2 new Energy α (2A)2  new Energy α 4A2 ⇒new energy becomes 4 times when compared to eqn(1).


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