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If the angle between the vectors $\vec{A} and \vec{B}$ is $θ$ , the value of the product $\vec{(B} \times \vec{A} \vec{) . A}$ is equal to

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Correct option is D

We know that scalar product is cyclic,B→ ×A→.A→ = (A→×B→).A→A→ ×A→.B→ = 0.B→ = 0

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If the angle between the vectors A→ and B→ is θ, the value of the product (B→ ×A→).A→ is equal to

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If the angle between the vectors $\vec{A} and \vec{B}$ is $θ$ , the value of the product $\vec{(B} \times \vec{A} \vec{) . A}$ is equal to