If the angle between the vectors A→ and B→ is θ, the value of the product (B→ ×A→).A→ is equal to
BA2cosθ
BA2sinθ
BA2sinθcosθ
zero
We know that scalar product is cyclic,
B→ ×A→.A→ = (A→×B→).A→
A→ ×A→.B→ = 0.B→ = 0