If the angle of projection of a projector with same initial velocity exceed or fall short of 45° by equal amount α, then the ratio of horizontal ranges is                             [Kerala CEE 2014]

Given,  θ1 = θ2 = 450θ1 + θ2 = (450 + α) + (450 - α) = 900u1 = u2 = u  ⇒ R1 = R2 = ?R1=u12sinθ1+θ2g⇒  R1=u2sin90°g=u2g                 ……..(i)Similarly,  R2=u22sinθ1+θ2g⇒ R2=u2sin90°g=u2g                ……..(ii)The ratio of horizontal rangesR1R2=u2/gu2/g=1:1⇒  R1:R2=1:1