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Q.

If angular displacement of a particle moving on a curved path be given as,θ=1.5t+2t2 where  t is in sec, the angular velocity at t = 2 sec, will be- (in rad/sec.)

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a

1.5

b

2.5

c

9.5

d

8.5

answer is C.

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Detailed Solution

θ=1.5t+2t2,∴dθdt=1.5+4t, Now, at t = 2 sec , dθdt=1.5+4×2=1.5+8=9.5rad/sec
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