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If $λ_{1}$ and $λ_{2}$ are the wavelengths of the first members of the Lyman and Paschen series, respectively, then $λ_{1} : λ_{2}$ is

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Correct option is D

For Lyman series, n1=1 and n2=2 for first line 1λ1=R112−122=R11−14=3R4 For Paschen series, n1=3 and n2=4 for first line ∴ 1λ2=R132−142=R19−116=7R144λ1λ2=4/3R144/7R=7108

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If λ1 and λ2 are the wavelengths of the first members of the Lyman and Paschen series, respectively, then λ1:λ2 is

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If $λ_{1}$ and $λ_{2}$ are the wavelengths of the first members of the Lyman and Paschen series, respectively, then $λ_{1} : λ_{2}$ is