Q.

If  an artificial satellite is moving in a circular orbit around the earth with a speed equal to half themagnitude of the escape velocity from the earth, the height of the satellite above the surface of the earth is

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a

2 R

b

R2

c

R

d

R4

answer is C.

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Detailed Solution

We know that,  vo=12×ve                          …(i)∵  vo=GMeRe+hx and ve=2GMeRePutting these values in Eq. (i), we getGMeRe+h=122GMeRe⇒  GMeRe+h=12×12×2GMeRe⇒  Re+h=2Re⇒  h=Re or R
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