Q.

If the atmospheric pressure is 76 cm of mercury at what depth of water the pressure will becomes 3 atmospheres

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a

11m

b

21m

c

31 m

d

41 m

answer is B.

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Detailed Solution

Presence at a given depth = Atmospheric pressure + pressure due to liquid3P0=P0+hdwg2×1.013×105=h×103×9.8⇒h=20.6m
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