Questions
If atomic mass of Th is 232 and its atomic number is 90. If it forces 4 -particles and some -particles. The mass number of final stable element is 208 and atomic number 82. How many -particles are emitted during this process?
detailed solution
Correct option is D
90Th232→82Pb208+x 2He4+4 −1e0 Balancing mass no, 232 =208 + 4x + 0 ⇒x=6 Or, Balancing atomic no, 90=82 + 2x -4 ⇒x=6when a beta particle is emitted by a nucleus mass number of the nucleus remains same but its atomic number will be increased by one , when an alpha particle is emitted by the nucleus its mass number will be decreased by 4 and atomic number will be decreased by 2.Talk to our academic expert!
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