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Questions  

If atomic mass of   Th  is 232 and its atomic number is 90. If it forces 4 β -particles and some α-particles. The mass number of final stable element is 208 and atomic number 82. How many α-particles are emitted during this process?

a
3
b
5
c
4
d
6

detailed solution

Correct option is D

90Th232→82Pb208+x 2He4+4 −1e0  Balancing mass no,  232 =208 + 4x + 0 ⇒x=6 Or, Balancing atomic no, 90=82 + 2x -4 ⇒x=6when a  beta particle is emitted by a nucleus  mass number of the nucleus remains same but its atomic number will be increased  by one , when an alpha particle is emitted  by the nucleus its mass number will be decreased by 4 and atomic number will be decreased by 2.

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A proton, within a nucleus decays into a neutron during a process called β+ decay which occurs is some unstable nuclei. This process is represented by the equation

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